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Although the final answer was less than 2, the calculation used a number as high as 180. The highest number used will grow as the number of decimal digits grows, rather than as the value of the result increases. You can see this by invoking the show your work to the teacher clause included in the function; it can be invoked by setting verbose to 63. With only a few decimal places, we can see that the integers remain well within the limits: $ verbose=63 fpmul 3.14 4.5 fp_tot=$(( 1 * 314 )) fp_tot=$(( 314 * 45 )) fp_tot=14130 14.13 When the number increases, even though each operand has only two digits, the integers being used in the calculations grow quickly. This calculation succeeds in bash with 64-bit integers, but fails in ash with only 32 bits: bash 2.05b: $ verbose=63 fpmul 1.2 3.4 5.6 7.8 9.8 7.6 5.4 fp_tot=$(( 1 * 12 )) fp_tot=$(( 12 * 34 )) fp_tot=$(( 408 * 56 )) fp_tot=$(( 22848 * 78 )) fp_tot=$(( 1782144 * 98 )) fp_tot=$(( 174650112 * 76 )) fp_tot=$(( 13273408512 * 54 )) fp_tot=716764059648 71676.4059648 ash: $ fpmul 1.2 3.4 5.6 7.8 9.8 7.6 5.4 fpmul: overflow error: -495478784 The Script . standard-funcs _fpmul() { fp_places= fp_tot=1 fp_qm= fp_neg= _FPMUL= for fp_n do ## 2 negatives make a positive, i.e., each negative number changes the sign case $fp_n in -*) [ "$fp_neg" = '-' ] && fp_neg= || fp_neg='-' fp_n=${fp_n#-} ;; esac

In addition to creating new partitioned tables and indexes, SQL Server also exposes capabilities for DBAs to partition existing tables, modify range boundaries of existing functions and schemes, and swap data in and out of partitions. Partitioning an existing table can be done in one of two ways. The easier method is to create a clustered index on the table, partitioned using whatever partition scheme the DBA wishes to employ. The other method requires manipulation of partition functions and will be covered in the next section, Modifying Partition Functions and Schemes. Assume that in the same database that contains the SalesAmounts table and related partition function and schemes there exists the following table, which contains times that customers visited the store: CREATE TABLE Visitors ( VisitorId INT NOT NULL, VisitDate DATETIME NOT NULL, CONSTRAINT PK_Visitors PRIMARY KEY (VisitorId, VisitDate) ) The DBA might wish to partition this table using the same scheme as the sales data, such that data in similar date ranges will share the same filegroups. This table already has a clustered index, implicitly created by the PK_Visitors primary key constraint. To partition the table, the constraint must be dropped. The constraint then must be re-created using a partition scheme. The following T-SQL code accomplishes that: SET XACT_ABORT ON BEGIN TRANSACTION ALTER TABLE Visitors DROP CONSTRAINT PK_Visitors ALTER TABLE Visitors ADD CONSTRAINT PK_Visitors PRIMARY KEY (VisitorId, VisitDate) ON ps_FiscalQuarter2005_Split (VisitDate) COMMIT To avoid inconsistent data, the entire operation should be carried out in a single transaction. SET XACT_ABORT is used to guarantee that runtime errors in the transaction will force a rollback.

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Converting this table back to a nonpartitioned table can be done using either the reverse operation (dropping the partitioned clustered index and re-creating the index nonpartitioned) or by modifying the partition function to have only a single partition.

## Check for non-numeric characters case $fp_n in ## (minus signs have been removed by this point, ## so we don't need to include them) *[!0-9.]*) return 1 ;; ## Use this in place of the line above if you prefer to ignore (i.e., skip over) ## invalid arguments ## *[!0-9.]*) continue ;; esac ## count the number of decimal places, ## then remove the decimal point and multiply case $fp_n in .*) fp_int= fp_dec=${fp_n# } fp_places=$fp_places$fp_dec fp_n=$fp_dec ;; *.*) fp_dec=${fp_n#*.} fp_int=${fp_n%.*} fp_places=$fp_places$fp_dec fp_n=$fp_int$fp_dec ;; esac ## remove leading zeroes while : do case $fp_n in 0*) fp_n=${fp_n#0} ;; *) break;; esac done ## "Show your work to the teacher" if verbose equals 63 [ ${verbose:-0} -eq 63 ] && printf "%s\n" "total=\$(( $fp_tot * $fp_n ))" ## multiply by the previous total fp_tot=$(( $fp_tot * $fp_n )) ## report any overflow error case $fp_tot in -*) printf "fpmul: overflow error: %s\n" "$fp_tot" >&2 return 1 ;; esac done

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